11h^2-6h-3=0

Solution for 11h^2-6h-3=0 equation:

11h^2-6h-3=0

a = 11; b = -6; c = -3;
Δ = b2-4ac
Δ = -62-4·11·(-3)
Δ = 168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{168}=\sqrt{4*42}=\sqrt{4}*\sqrt{42}=2\sqrt{42}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{42}}{2*11}=\frac{6-2\sqrt{42}}{22}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{42}}{2*11}=\frac{6+2\sqrt{42}}{22}
$